3.31 \(\int \frac {1}{\sqrt {3+3 x^2-2 x^4}} \, dx\)

Optimal. Leaf size=45 \[ \sqrt {\frac {2}{\sqrt {33}-3}} F\left (\sin ^{-1}\left (\frac {2 x}{\sqrt {3+\sqrt {33}}}\right )|\frac {1}{4} \left (-7-\sqrt {33}\right )\right ) \]

[Out]

EllipticF(2*x/(3+33^(1/2))^(1/2),1/4*I*6^(1/2)+1/4*I*22^(1/2))*2^(1/2)/(-3+33^(1/2))^(1/2)

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Rubi [A]  time = 0.07, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {1095, 419} \[ \sqrt {\frac {2}{\sqrt {33}-3}} F\left (\sin ^{-1}\left (\frac {2 x}{\sqrt {3+\sqrt {33}}}\right )|\frac {1}{4} \left (-7-\sqrt {33}\right )\right ) \]

Antiderivative was successfully verified.

[In]

Int[1/Sqrt[3 + 3*x^2 - 2*x^4],x]

[Out]

Sqrt[2/(-3 + Sqrt[33])]*EllipticF[ArcSin[(2*x)/Sqrt[3 + Sqrt[33]]], (-7 - Sqrt[33])/4]

Rule 419

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1*EllipticF[ArcSin[Rt[-(d/c),
2]*x], (b*c)/(a*d)])/(Sqrt[a]*Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] &
& GtQ[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-(b/a), -(d/c)])

Rule 1095

Int[1/Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Dist[2*Sqrt[-c], I
nt[1/(Sqrt[b + q + 2*c*x^2]*Sqrt[-b + q - 2*c*x^2]), x], x]] /; FreeQ[{a, b, c}, x] && GtQ[b^2 - 4*a*c, 0] &&
LtQ[c, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {3+3 x^2-2 x^4}} \, dx &=\left (2 \sqrt {2}\right ) \int \frac {1}{\sqrt {3+\sqrt {33}-4 x^2} \sqrt {-3+\sqrt {33}+4 x^2}} \, dx\\ &=\sqrt {\frac {2}{-3+\sqrt {33}}} F\left (\sin ^{-1}\left (\frac {2 x}{\sqrt {3+\sqrt {33}}}\right )|\frac {1}{4} \left (-7-\sqrt {33}\right )\right )\\ \end {align*}

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Mathematica [C]  time = 0.05, size = 50, normalized size = 1.11 \[ -i \sqrt {\frac {2}{3+\sqrt {33}}} F\left (i \sinh ^{-1}\left (\frac {2 x}{\sqrt {-3+\sqrt {33}}}\right )|\frac {1}{4} \left (-7+\sqrt {33}\right )\right ) \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/Sqrt[3 + 3*x^2 - 2*x^4],x]

[Out]

(-I)*Sqrt[2/(3 + Sqrt[33])]*EllipticF[I*ArcSinh[(2*x)/Sqrt[-3 + Sqrt[33]]], (-7 + Sqrt[33])/4]

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fricas [F]  time = 0.82, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-2 \, x^{4} + 3 \, x^{2} + 3}}{2 \, x^{4} - 3 \, x^{2} - 3}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-2*x^4+3*x^2+3)^(1/2),x, algorithm="fricas")

[Out]

integral(-sqrt(-2*x^4 + 3*x^2 + 3)/(2*x^4 - 3*x^2 - 3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-2 \, x^{4} + 3 \, x^{2} + 3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-2*x^4+3*x^2+3)^(1/2),x, algorithm="giac")

[Out]

integrate(1/sqrt(-2*x^4 + 3*x^2 + 3), x)

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maple [B]  time = 0.08, size = 84, normalized size = 1.87 \[ \frac {6 \sqrt {-\left (-\frac {1}{2}+\frac {\sqrt {33}}{6}\right ) x^{2}+1}\, \sqrt {-\left (-\frac {1}{2}-\frac {\sqrt {33}}{6}\right ) x^{2}+1}\, \EllipticF \left (\frac {\sqrt {-18+6 \sqrt {33}}\, x}{6}, \frac {i \sqrt {6}}{4}+\frac {i \sqrt {22}}{4}\right )}{\sqrt {-18+6 \sqrt {33}}\, \sqrt {-2 x^{4}+3 x^{2}+3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-2*x^4+3*x^2+3)^(1/2),x)

[Out]

6/(-18+6*33^(1/2))^(1/2)*(1-(-1/2+1/6*33^(1/2))*x^2)^(1/2)*(1-(-1/2-1/6*33^(1/2))*x^2)^(1/2)/(-2*x^4+3*x^2+3)^
(1/2)*EllipticF(1/6*x*(-18+6*33^(1/2))^(1/2),1/4*I*6^(1/2)+1/4*I*22^(1/2))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {-2 \, x^{4} + 3 \, x^{2} + 3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-2*x^4+3*x^2+3)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/sqrt(-2*x^4 + 3*x^2 + 3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{\sqrt {-2\,x^4+3\,x^2+3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(3*x^2 - 2*x^4 + 3)^(1/2),x)

[Out]

int(1/(3*x^2 - 2*x^4 + 3)^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\sqrt {- 2 x^{4} + 3 x^{2} + 3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-2*x**4+3*x**2+3)**(1/2),x)

[Out]

Integral(1/sqrt(-2*x**4 + 3*x**2 + 3), x)

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